If sin theta = -0.89 determine two possible values for theta if 0 degrees < theta < 360.
\[\sin(\theta) = -0.89\] \[\theta = \sin^-1(-0.89)\] That could be one possible way of figuring out an angle.
okay. any other?
Not sure since you have a negative 0.89.
You may be able to find another if it is not exactly the same by using:\[\sin^-1(\theta) = \frac{ 1 }{ \sin(\theta) } = \csc(\theta)\]
But you can not have a negative angle based on your 0 < theta < 360
Another way is adding or removing revolutions around the circle so |dw:1405832312572:dw|
|dw:1405834567223:dw| hope that makes sense arcsin or inverse sin will give 2 angles both with equal reference angles doing the arcsin of pos value yields the reference angle allowing you to find 2 angles in 3rd and 4th quadrants
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