Question

Please help me with this question.
log(x - 1) = -log 2

Answer 1

Remember that a multiplier of the log is an exponent.

\(\large a \log b = \log b^a\)

Ok?

Answer 2

yes, i understand.

Answer 3

Then let's start.

\(\log(x - 1) = -\log 2\)

\(\log(x - 1) = -1 \times\log 2\)

\(\log(x - 1) = \log 2^{-1}\)

\(x - 1 = 2^{-1} \)

\(x - 1 = \dfrac{1}{2} \)

\(x = 1 + \dfrac{1}{2} \)

\(x = \dfrac{3}{2} \)