Question

@ganeshie8 ,@Catch.me ,@Abhisar ,I don't understand this question...Please explain for me...
A bullet of mass m moving with velocity u penetrates a piece of stationary plasticine of mass M.The bullet emerges from the piece of plasticine with velocity v in the same direction as the initial direction of the bullet and the plasticine attached to the bullet has same mass as that of the bullet.The velocity of the remaining plasticine immediately after the bullet emerges from it can be expressed as?

Answer 1

You could use conservation of momentum here. In all collisions momentum is conserved.

Answer 2

Can you explain what is conservation of momentum?

Answer 3

@Abhisar What is recoil velocity?

Answer 4

are u asking in general or in this question ?

Answer 5

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar
for this question u can use m1u1 + m2u2 = m1v1 + m2v2
\(\color{blue}{\text{End of Quote}}\)

Answer 6

I ask for general..

Answer 7

Recoil is the backward movement or jerk that a gun experiences after firing a bullet. Recoil velocity is the velocity of recoil.

Answer 8

How to do this question?
Figure 3.25 shows two blocks of masses,2m and 3m,that are connected by an inelastic stringbetween them.Thet are pulled by a constant force,F,on a smooth horizontal surface.

If the tension of the string is T,what is the value of F in terms of T?