Help!!!
Graph y = –2x^2 + 6. Describe what you see.
just graph it.
But I'm not sure about the "describe what you see" part, what do they want to hear about it exactly?
describe means answering the questions 1/ Whether the parabola up or down 2/Where is the vertex? 3/ Where is the roots?( x-intercept) 4/ Where is the y-intercept Optional: domain, range. That's it
Yeah and most of that I don't know T-T
hahaha... so, you have to graph it first.!!
I did
show me your graph
I meant I don't know it as in I literally don't know how to answer those things you listed
to you, is it upward or downward?
I suppose downward because that's where it eventually goes? O.o I think I'm wrong though haha
yes, it is. it is downward next, click at vertex, what do you see?
Is the vertex it's highest point?
yup
Woah I'm just an awesome guesser today! Okay so the vertex is (0,6) right?
The vertex is the y-intercept in this one O.O *mind blown*
yup, next, click at 2 points where the graph "cut" x-intercept, what do you see?
Like both places where it crosses the x line?
yup
I notice it's( -1.73,0) and (1.73,0) so if we subtracted them it would = 0, does that mean something? o.o
no, it is just the roots of the graph, and you can make conclusion on it by saying: the roots are \(\pm 1.73\) Now, we have all of them, just summary. Hey!! you do your own conclusion, I do mine, we compete. ok? I say COMPETE, not COMPARE, dare you?? hahaha...
hahaha okay!
The graph of y=-2x^2+6 shows us that it is a downward parabola that has it's roots at \[\pm 1.73\] and it's vertex placed at (0,6)
Breaks out of the comments box, through the ad, and off into the distance...
{the graph of y=-2x^2+6 is a downward parabola with the vertex at (0,6). \(\\ Its roots are x=-1.73 and x=1.73\ The parabola has y-intercept at y =6. Domain is (-\infty, \infty), range is (-\infty, 6)}
gtg
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