Question

The temperature of a chemical reaction ranges between 20°C and 160°C. The temperature is at its lowest point when t = 0, the temperature is 90 degrees and increasing. What is a sine function that would model this reaction?

Answer 1

The Answers are:

f(t) = 90 sin pi over 4t + 70

f(t) = 70 sin pi over 4t + 90

f(t) = 70 sin 8t + 90

f(t) = 90 sin 8t + 70

Answer 2

I am thinking its B or C since the Amplitude is 70 and the Vertical Shift is 90.

Answer 3

@ganeshie8

Answer 4

In the second choice, is t in the denominator or the numerator?

Answer 5

Neither, you are multiplying it to pi/4.

Answer 6

\(\Large \sin(\frac{\pi}{4}t)\)?

Answer 7

\[f(t)=70\sin(\pi/4)t+90\]

Answer 8

Is the second answer

Answer 9

Put t= 0 in each answer choice and evaluate f(t). It should be 90. You can quickly rule out two of the choices.

Answer 10

???

Answer 11

Something doesn't seem right. It says the temperature ranges from 20 to 160. That means the lowest temperature is 20. But then it says: "temperature is at its lowest point when t = 0, the temperature is 90 degrees" implying the lowest temperature is 90 degrees!???

Answer 12

I don't know, this question is strange.

Answer 13

Can you post a screenshot of the question and the answer choices?

Answer 14

I think its B

Answer 15

Or maybe C?

Answer 16

Both b and c satisfy all the other conditions except the "temperature is at its lowest point when t = 0".

Answer 17

I will just answer B

Answer 18

Try B. If it does not accept that, try C.
But I think there may be an error in the question.

Answer 19

K

Answer 20

Since your here, can you help with this other question?

Answer 21

I can try.

Answer 22

The graph of the sine curve below is of electromagnetic energy that represents red light:

Answer 23

What function accurately represents the sine curve for red light?

Answer 24

From the graph, the period is 640 nanometers.
In f(theta) = Asin(B * theta), the period is 2pi / B
Equate 2pi/B to 640 and solve for B.

Answer 25

The Answers are:

A:f(x) = sin pi over 640x

B:f(x) = sin 640πx

C:f(x) = sin 320πx

D:f(x) = sin pi over 320x

Answer 26

I can't give answers.
Equate 2pi/B to 640 and solve for B.
Then put it in f(x) = sin(B * x)

Answer 27

what was the answer to your original question?

Answer 28

like was it b or c?

Answer 29

@Johnny_Boy_14

Answer 30

???

Answer 31

It was C

Answer 32

I think

Answer 33

okay thank you!