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2x-10/x^2-3x-10 multiplied by x^2-4/8x-16
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Start by factoring
factor completely, cancel terms out, multiply
but the 8x-16 part is getting me confused what would it cancel with
factor out of 8
\(\LARGE\color{blue}{ \frac{2x-10}{x^2-3x-10} \times \frac{x^2-4}{8x-16} }\) \(\LARGE\color{blue}{ \frac{2(x-5)}{(x-5)(x+2)} \times \frac{(x-2)(x+2)}{8(x-4)} }\)
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