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how do i prove this is false? equation in comments
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\[\sum_{x=1}^{n} x+1 =[\sum_{x=1}^{n} x] +1\]
well its true
lets prove it
wanna use direct proof ?
but if i say in is 3 or 4 they don't equal the same?
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*n
wait wait is it like this \(\sum_{x=1}^{n}[ x+1] =[\sum_{x=1}^{n} x] +1\)
?
yes
ohh then its false :)
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\(\sum_{x=1}^{n}[ x+1] =[\sum_{x=1}^{n} x] + \sum_{x=1}^{n} 1 =[\sum_{x=1}^{n} x] +n\)
so since its false sentense u only to show a counter example , and as u say when n=3 \(\sum_{x=1}^{3} x+1 =[\sum_{x=1}^{3} x] +1\) but \(9\neq 7\)
got it nw ?
yup. Thanks!
np :)
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