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Mathematics 17 Online
OpenStudy (anonymous):

how do i prove this is false? equation in comments

OpenStudy (anonymous):

\[\sum_{x=1}^{n} x+1 =[\sum_{x=1}^{n} x] +1\]

OpenStudy (ikram002p):

well its true

OpenStudy (ikram002p):

lets prove it

OpenStudy (ikram002p):

wanna use direct proof ?

OpenStudy (anonymous):

but if i say in is 3 or 4 they don't equal the same?

OpenStudy (anonymous):

*n

OpenStudy (ikram002p):

wait wait is it like this \(\sum_{x=1}^{n}[ x+1] =[\sum_{x=1}^{n} x] +1\)

OpenStudy (ikram002p):

?

OpenStudy (anonymous):

yes

OpenStudy (ikram002p):

ohh then its false :)

OpenStudy (ikram002p):

\(\sum_{x=1}^{n}[ x+1] =[\sum_{x=1}^{n} x] + \sum_{x=1}^{n} 1 =[\sum_{x=1}^{n} x] +n\)

OpenStudy (ikram002p):

so since its false sentense u only to show a counter example , and as u say when n=3 \(\sum_{x=1}^{3} x+1 =[\sum_{x=1}^{3} x] +1\) but \(9\neq 7\)

OpenStudy (ikram002p):

got it nw ?

OpenStudy (anonymous):

yup. Thanks!

OpenStudy (ikram002p):

np :)

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