what is an equation of the line that passes through the point (4 −6) and has a slope of −3
use y=mx+b your slope is -3 m=-3 y=-3x+b now we need to figure out the "b" value that is your y intercept
\(\bf \begin{array}{lllll} &x_1&y_1\\ &({\color{red}{ 4}}\quad ,&{\color{blue}{ -6}})\quad \end{array} \\\quad \\ slope = {\color{green}{ m}}= -3 \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)
(4,-6) was given to you this means x=4 and y=-6
y=mx+b -6=-3(4)+b finish solving for b
Please solve in writing formation
writing formation what is that?
typed
am I not typing???????? ok sorry don't know what to tell you the problem is 99% done, just solve for b or use the other formula provided by jdoe0001
@Clalgee
?
@precal
@algebra1helplikern
@abram.macedonio which part did you not understand from @precal ' s explanation?
all dude
@zzr0ck3r
hmm looks to me pretty straightforward above
I need some one to solve clearly
\(\bf \begin{array}{lllll} &{\huge x_1}&{\huge y_1}\\ &({\color{red}{ 4}}\quad ,&{\color{blue}{ -6}})\quad \end{array} \\\quad \\ slope = {\color{green}{ m}}= -3 \\ \quad \\ y-{\color{blue}{ {\huge y_1}}}={\color{green}{ m}}(x-{\color{red}{ {\huge x_1}}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)
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