Mathematics
8 Online
OpenStudy (anonymous):
I need the square root of x+2=X...
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OpenStudy (tanya123):
sqrt(x+2) = X
OpenStudy (anonymous):
\[\sqrt{x+2}=x\]
just like that
OpenStudy (anonymous):
yes what? I need to solve that.
OpenStudy (tanya123):
x = X^2-2
OpenStudy (tanya123):
So, x = -2
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OpenStudy (anonymous):
wouldn't it be \[x+2=x ^{2}\] ?
OpenStudy (anonymous):
Oh, I think I see what your saying
OpenStudy (anonymous):
just a sec
OpenStudy (tanya123):
Should look like this,
http://prntscr.com/44rhng
I'm not able to make it in the laTex form
OpenStudy (anonymous):
but i'd have to preform the operation \[x ^{2}\]/x while subtracting 2
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OpenStudy (tanya123):
Hold on, he'll explain you @TwinYang
OpenStudy (anonymous):
as in, Simultaneously?
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
steps.
OpenStudy (anonymous):
anything else?
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OpenStudy (anonymous):
Do I need to type new quiestions in as that?
OpenStudy (anonymous):
what do you mean?
OpenStudy (anonymous):
Wait, why did you multiply all terms in the equation by -1
OpenStudy (anonymous):
because we used the polynomial method to get it
OpenStudy (anonymous):
polynomial method. Got it. I'll need to write a note on that. I didn't pay much attention this week, and i'm suffering for it.
Thank you.
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OpenStudy (anonymous):
welcome