Question

does anyone know the answer. Write the simplest polynomial function with zeros 4+i and square root 2

Answer 1

lets consider a function
\[f(x)=(x-a)(x-b)\]
for this this function zeroes are
a and b
so in ur problem zeroes are given ----4 + i, √2
now again (4+i) is a complex root so its conjugate is also a root, which is (4 - i)
so u've got 3 roots they are---(4+i),(4-i) and √2
so the polynomial will be simply---
\[(x - (4 + i))*(x - (4 - i))*(x - √2)\]

Answer 2

now its just calculation