Question

An auditorium earned $30,000 in sold−out concert ticket sales. Front section tickets cost $75 per seat and back section tickets cost $50 per seat. The number of front section seats is twice the number of back section seats. How many seats are in the front section?

Answer 1

@iGreen

Answer 2

f = front section tickets
b = back section tickets

75f + 50b = 30,000
f = 2b
now sub 2b in for f in the other equation

75(2b) + 50b = 30,000 -- distribute
150b + 50b = 30,000
200b = 30,000
b = 30,000/200
b = 150

f = 2b
f = 2(150)
f = 300

check..
75f + 50b = 30,000
75(300) + 50(150) = 30,000
22,500 + 7500 = 30,000
30,000 = 30,000 (correct)

front seat (f) = 300
back seat (b) = 150

Answer 3

thanks!

Answer 4

no problem :)