Question

I am having difficulty finding 3 points for 3x-2y=0. Please help.

Answer 1

pick a value for x and then solve for y. the pair (x, y) give a point.

Answer 2

you there?

Answer 3

yep just trying out the equation so 0 is the value for x 3(0)-2y=0?

Answer 4

so what does y have to be?

Answer 5

y would have to be 0

Answer 6

excellent! so now you have one point, (0, 0).

pick another value for x

Answer 7

lets use 1 3(1)=2y-0 x=3

Answer 8

hold on there...
if x = 1, then 3(1)-2y=0 => 2y=3 so what is y?

Answer 9

3x-2y=0 3(1) =3 -2y=0 x=3 that is the part I am stuck on?

Answer 10

so the y would be 3/2 so it will not work for graphing

Answer 11

first off, we specifiy x so we already know what it is. we specifiy that x = 1, this gives us...

3x - 2y = 0 so with x = 1 => 3(1) - 2y = 0 => 3 - 2y = 0

the goal here is to find out what of y goes with x = 1.

and yes, is see you have y = 3/2. Awesome!

Answer 12

if you don't want fractions, use multiples of 2 for your x values.

Answer 13

3(2)-2y=0 x=6 y =6/-2= -3

Answer 14

3(2)-2y=0 => 2y=6 and y = 3

Answer 15

Is there a limit of values that I can use for x,y ,

Answer 16

how do you know when to use a negative or positive, is that dependent on the if the line is going straight or not

Answer 17

no, just pick a value for x and you can find the corresponding values of y. in fact, you can solve the equation for y, which will directly specify the y value for any given x value:

3x-2y=0 now add 2y to both sides and get

3x = 2y + 0 = 2y => 2y = 3x (equality)

now divide bith sides by 2 and get

\[y=\frac{ 3 }{ 2 }x\]

Answer 18

so when x = 0 => y = 3/2 (0) = 0 => (x, y) = (0, 0)

when x = 2 => y = 3/2 (2) = 3 => (x, y) = (2, 3)

pick another value for x... preferably a multiple of 2.

Answer 19

if I chose -2 -3(-2)=6 6/-2= -3 x=-2, y=-3

Answer 20

thanks man appreciate the help, this section was driving me bonkers. how do i give you a medel

Answer 21

very good! sorry was talking to someone here. just click on the "best response" button, but no worries. just happy to help!

Answer 22

I appreciate it alot

Answer 23

you're welcome!!!