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Mathematics 19 Online
OpenStudy (anonymous):

Can anyone help?

OpenStudy (anonymous):

OpenStudy (solomonzelman):

If `AB=6`, then `CD=6`. ──────────── You know that `BD=10` ──────────── Use `a²+b²=c²` to find CD ──────────── After you find CD, you will know that AC=12 (As AB+BC = 6+6 = 12) ────────────\ After you know AC, and CD use `a²+b²=c²` again to find AD.

OpenStudy (solomonzelman):

These are the steps to your problem.

OpenStudy (anonymous):

is CD 136?

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (solomonzelman):

CD can't possibly be 36.

OpenStudy (anonymous):

whoops my bad didn't mean that!

OpenStudy (solomonzelman):

BC is 6. BD is 10. 6² + `CD`² = 10² 36+ `CD`² = 100 `CD`² = 64 `CD` = 8

OpenStudy (anonymous):

okay but what step is next?

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (solomonzelman):

CD=10 AC=12 AD=?? `CD`² + `AC`² = `AD`² `10`² + `12`² = `AD`² 100 + 144 = `AD`² 244 = `AD`² `AD` = 2√61 ≈ 15.62

OpenStudy (anonymous):

Its not one of the choices tho? @SolomonZelman

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