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If `AB=6`, then `CD=6`. ──────────── You know that `BD=10` ──────────── Use `a²+b²=c²` to find CD ──────────── After you find CD, you will know that AC=12 (As AB+BC = 6+6 = 12) ────────────\ After you know AC, and CD use `a²+b²=c²` again to find AD.
These are the steps to your problem.
is CD 136?
@SolomonZelman
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CD can't possibly be 36.
whoops my bad didn't mean that!
BC is 6. BD is 10. 6² + `CD`² = 10² 36+ `CD`² = 100 `CD`² = 64 `CD` = 8
okay but what step is next?
@SolomonZelman
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CD=10 AC=12 AD=?? `CD`² + `AC`² = `AD`² `10`² + `12`² = `AD`² 100 + 144 = `AD`² 244 = `AD`² `AD` = 2√61 ≈ 15.62
Its not one of the choices tho? @SolomonZelman
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