PLease Help will fan and give medal! :3 Expand and then simplify the expression (a + 2)(a + 2)
\[(a+b)^2=a^2+2ab+b^2\] always put \(a=a,b=2\)
there is no b @satellite73
Could you show me the steps on how to solve it please?
here is one way. rename the first (a+2) as A so the problem is A(a+2) now distribute the A. Can you do that ?
distribute the A means multiply each term in the parens by A
yeah I can
what do you get ?
Would it be a^2+2a?
I should have used a different letter than A. let's use d= (a+2) so the problem is d(a+2) now what do you get?
you should get ad + 2d
Yeah that's what I got
now we remember that d is short for (a+2) and write ad+2d as a(a+2) + 2(a+2) now we have two problems that you know how to do. distribute the a and distribute the 2 all together what do you get ?
Here is a video, when you have time, http://www.khanacademy.org/math/algebra/multiplying-factoring-expression/multiplying-binomials/v/multiplying-binomials
Thank you. I'll watch it. I can understand things better if i can hear and see what's going on. Not so good online.
ok, post your answer when you get it.
a^2+4a+4
yes. notice satellite's post gave the "short way" also, if we finished a(a+2) + 2(a+2) we get a^2 + 2a + 2a+ 4 and that simplifies to a^2 +4a + 4 (but if you watched the video, you know that!)
Lol yeah I did. Thank You so much. :)
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