Choose the equation below whose axis of symmetry is x = 2.

y = x^2 + 4x + 2

y = x^2 − 4

y = x^2 − 2

y = x^2 − 4x + 2

Question

Choose the equation below whose axis of symmetry is x = 2.

 y = x^2 + 4x + 2

 y = x^2 − 4

 y = x^2 − 2

 y = x^2 − 4x + 2

anonymous · Answer

@jim_thompson5910

imstuck · Answer

I can help you unless you want to wait for jim_thompson5910

anonymous · Answer

ima say A

jim_thompson5910 · Answer

you can go ahead IMStuck

jim_thompson5910 · Answer

hint: the axis of symmetry of y = ax^2 + bx + c is x = -b/(2a)

anonymous · Answer

@IMStuck I would appreciate your assistance.

anonymous · Answer

I put A but I wanted to double check my answers

anonymous · Answer

sorry D the formula is -b/a that would make the -4 positive

anonymous · Answer

if you go with A (my first answer) the answer would turn negative i forgot about the formula

anonymous · Answer

Functions 1 and 2 are shown below.

Function 1: f(x) = −3x2 + 2
A graph of a parabola with x intercepts of negative 0.5, 0 and 2, 0 and a vertex of 0.5, 4 is shown.

Which function has a larger maximum? Type your answer as 1 or 2.

anonymous · Answer

The 2 in function 1 is an exponent btw

anonymous · Answer

-3x^2+2