Question

help me plzzz


Solve for y.

y/4-(y-1)/2=>3

Answer 1

Okay, so the first thing you need to do is make the bottom denominator of (y/4)-(y/1) the same. This basically turns into (y/4)-(4y/4).
From there you get y-4y/4 or -3y/4.
With that now you need to divide -3y/4 by 2/1 (or 2).
When you divide two numbers, you need to flip the second one and change the sign to multiplication, so now the equation becomes -3y/4*1/2.

Answer 2

Now that you have -3y/4*1/2, you multiply and get \[-3y/8 \ge 3\].
If you multiply 8 on both sides you get \[-3y \ge 24\]
When you divide negative numbers in an equation such as this, the greater than sign is flipped, therefore leading the answer to be \[y \le -8\]

Hope this helped!