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help me plzzz Solve for y. y/4-(y-1)/2=>3
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Is this the inequality? \(\Large \frac{y}{4} + \frac{y-1}{2} \ge 3 \)
yes
I realized I made a mistake in the sign. Is this the one? Check carefully \(\Large \frac{y}{4} - \frac{y-1}{2} \ge 3\)
oh my bad it look good. :)
Okay. Multiply throughout by 4 to get rid of the fraction: \(\large \frac{y}{4}*4 - \frac{y-1}{2}*4 \ge 3*4 \) = \(\large y - 2(y-1) \ge 12\) \(\large y - 2y+2 \ge 12\) \(\large -y+2 \ge 12\) \(\large -y \ge 10\) \(\large y \le 10\)
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The last line should be: \(\Large y \le -10\) That is, y is less than or equal to minus 10.
hey thanks
you are welcome.
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