Question

Find the difference ten and two-ninths minus seven and two-thirds. Be sure to reduce to simplest form.

four and five-ninths

three and zero-sixths

two and five-ninths

three and four-ninths

Answer 1

\(\ \cal 10\dfrac{2}{9} ~\longrightarrow \dfrac{(10*9) + 2}{9 } = \dfrac{92}{9} \)

\(\ \sf 7\dfrac{2}{3} \longrightarrow \dfrac{(7 * 3) + 2}{3} = \dfrac{23}{3} \)

Now you need to make their denominators the same to subtract them.

\(\ \sf \dfrac{92}{9} - \dfrac{23}{3} \)

Answer 2

so 23/9 ??

Answer 3

An easy way I would do this is by multiplying the denominators by each other. And what you do to the bottom you must do to the top.

\(\ \sf \dfrac{92}{9} \times 3 \) technically this would be 3/1 but you're multiply both top and bottom by 3.

And \(\ \sf \dfrac{23}{3} \times 9\)

Now you have \(\ \sf \dfrac{276}{27} - \dfrac{207}{27} \) now subtract them! The denominators stay the same. then simplify.