Question

help me out please? will fan and give medal

Answer 1

Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6).

a) y = 1 over 3x + 7
b) y = -3x + 3
c) y = 1 over 3x + 3
d) y = -3x + 7

Answer 2

Alright. Go ahead and plug your point (-1, 6) in y = mx + b, with the slope = -3 or m = -3 and solve for the y-intercept, b.

Answer 3

y = mx + b (Slope-Intercept Form)
y = -3x + b (We use (m=-3) because the line is parallel and needs the same slope)
6 = -3(-1) + b (We use (-1, 6) as our x, y)

6 = 3 + b
3 = b

OK, so our y-intercept of the new equation going through the point (-1, 6) is
(0, 3). Sweet.

So if we use the slope -3, and the y-intercept at (0, 3)

We can make: y = -3x +3

That's a parallel line passing through the point (-1, 6) =)))