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sin x cos x - 2 cos x = 0 how would you solve that? what identities?
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sin x cos x - 2 cos x = 0 cosx (sinx -2) =0 either cos x =0 or sinx -2 =0 but sinx -2 =0 means sinx =2 wihch is not possible so cosx =0 so x =(2n+1) *(pi/2) n being integer
the solution would be 90 degrees right?
and 3pi/2
because cos is 0 at that point too right?
yup you put other integral values for n you may get 270 ,450 .... and so on
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alright cool thanks
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