Question

solve: (x-5)^2+(x-5)-6=0

Answer 1

You will have to expand the (x-5)^2 and get this:

Answer 2

\[x ^{2}-10x +25+x-5-6=0\]then combine like terms.

Answer 3

\[x ^{2}-9x+14=0\]Then factor that. Yes?

Answer 4

That factors very nicely to (x-2)(x-7)=0

Answer 5

And there you have it!

Answer 6

or you can just solve it without multplying out
\[ (x-5)^2+(x-5)-6=0\]
\[(x-5-2)(x-5+3)=0\] etc