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Mathematics 16 Online
OpenStudy (anonymous):

Write the expression as a single logarithm, and simplify if possible. logc 2x + 5(logcx - logcy)

OpenStudy (cwrw238):

first simplify what's in the parentheses use the law of logs log a - log b = log (a/b)

OpenStudy (anonymous):

yea i did that part

OpenStudy (anonymous):

so what will i do with the parentheses

OpenStudy (cwrw238):

ok - you should have got logc (x/y) now 5 ( logc x/y) = logc ? can you do this bit?

OpenStudy (cwrw238):

use the law a log x = log x^a

OpenStudy (anonymous):

i got logc(7x/5y)

OpenStudy (cwrw238):

no its logc (x/y)^5

OpenStudy (cwrw238):

now you have logc 2x + logc (x/y)^5 what does this simplify to you need to apply the law log a + log b = log ab

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