Question

Please Help

Find the first six terms of the sequence.

a1 = -8, an = 5 • a(n-1)

Answer 1

n=2, you have an is a2, right? and a(n-1) is a1, right?
so a2 = 5 a1 = 5*(-8) =-40
what if n =3?? do the same, show me your work

Answer 2

5*-8(3-1)
5*-8(2)
5*-16
-80

Answer 3

-8, -40, -200, -1000, -5000, -25,000

-8, -40, -35, -30, -25, -20

0, 5, -40, -35, -30, -25

-40, -200, -1000, -5000, -25,000, -125,000

Answer 4

but -80 isn't one of the answers

Answer 5

@Bebong

Answer 6

of course it is not. hihihi. you apply the wrong rule.

Answer 7

oh...

Answer 8

\(a_n= 5*a_{n-1}\) , it is not \(a_n = 5 *(n-1)\)

Answer 9

so would a3 = -200

Answer 10

if n =3, then \(a_n ~~is~~a_3\) and \(a_{n-1}~~is~~a_2\)
you have a2 from the previous calculation, right? plug in

Answer 11

let check, a3 = 5*a2 =5*(-40) =-200 , yes!! you are correct

Answer 12

Thanks, I got it right!!