Question

Find the 6th term of the sequence: 8, 32, 128

Answer 1

I got 8192

Answer 2

so notice that each term after is multiplied by 4. 8 times 4 is 32. 32 times 4 is 128. 128 times 4 is 512. 512 times 4 is 2048. 2048 times 4 is 8192. The 6th term is 8192

Answer 3

Do u still need help?

Answer 4

I have another question

Answer 5

ok

Answer 6

find the 25th term of the sequence 22,26,30

Answer 7

I got 122. I added 4 to each number.

Answer 8

oh huh ok looks like @landshark5 gots it :P

Answer 9

I am the human calculator. :D

Answer 10

: P

Answer 11

instead of adding i multiplied 4 by 25 and got 100 and i added the 100 to the 22, I got 122. Its faster than just adding.

Answer 12

I got one more and this is my last question

Answer 13

Toby was asked to find the sum of the first 10 terms of the arithmetic sequence but he plugged something into the formula wrong! Where did he make his mistake? What should he have done instead?

Answer 14

7,4,1,-2...

Answer 15

who's Toby? lol jk :3

Answer 16

S10= 10/2 [2(7)+ (10-1)(3)]
=5[14 + 9 (3)]
= 5[14 + 27]
=5[41]
=205

Answer 17

Can you help?

Answer 18

ill try

Answer 19

is the s a variable

Answer 20

Please thank you so much

Answer 21

S is the part of the formula

Answer 22

i get it let me do the problem on paper

Answer 23

ok

Answer 24

I get 205 also. I can't find his mistake.

Answer 25

wait one more try.

Answer 26

Its like the order he did it or he plugged in the wrong thing

Answer 27

hey is the common difference 3 or -3?

Answer 28

look at your sequence of numbers
it is decreasing

Answer 29

the 10th term is in no way a bigger number than what you started with

Answer 30

what do you mean

Answer 31

7,4,1,-2...


this is your sequence
the numbers are getting smaller
how could the 10th number be bigger than the first number?
it can't

Answer 32

do you see what I'm saying?

Answer 33

basically this confirms you are using the wrong formula?

Answer 34

or toby

Answer 35

and that isn't a question