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Mathematics 19 Online
OpenStudy (fionacndg):

Find the value of x in the figure below if the volume is 234.9 m3.

OpenStudy (imstuck):

waiting for the figure below...

OpenStudy (fionacndg):

OpenStudy (fionacndg):

answer options x = 18.06 x = 54 x = 8.7 x = 9.03

OpenStudy (fionacndg):

@IMStuck

OpenStudy (imstuck):

The formula for the volume of a triangular prism is V=1/2(base)(height)(length)

OpenStudy (imstuck):

We know the volume already, so we have most of what need to do this.

OpenStudy (fionacndg):

so 234.9= 1/2*6*9*x ?

OpenStudy (imstuck):

\[234.9=\frac{ 1 }{ 2 }(6)(x)(9)\]

OpenStudy (imstuck):

That's right...what you typed! Now solve it for x.

OpenStudy (imstuck):

x=???

OpenStudy (fionacndg):

x= 8.7 ?

OpenStudy (imstuck):

yep! Good!

OpenStudy (fionacndg):

can you help me with this one? Find the surface area of the right triangular prism below.

OpenStudy (fionacndg):

OpenStudy (fionacndg):

@IMStuck

OpenStudy (imstuck):

BRB ok?

OpenStudy (fionacndg):

sure

OpenStudy (imstuck):

The formula for the surface area for that is this: SA=2B+(p)(h) where B is the area of the base (you have two of them, both triangles), p is the perimeter of the bases, and h is the height of the prism.

OpenStudy (fionacndg):

so what would the set up equation be ?

OpenStudy (imstuck):

We need to find the area of the triangles first. So let's do that.

OpenStudy (imstuck):

A=1/2(b)(h)...your values are 8 and 6, so A = 1/2(48) which is 24. So your bases are 24 each. NOW let's fill in the formula!

OpenStudy (imstuck):

Well we can't do that yet until we find the hypotenuse of the right triangle base. The legs are 6 and 8 so the hypotenuse is 10. We need that to find the perimeter of the base, p. So the perimeter is 6+8+10=24. Can we fill this formula in now, or what!?!?

OpenStudy (imstuck):

SA=2(24)+24(15) SA=48+360 SA=408 inches squared

OpenStudy (imstuck):

That's your answer!

OpenStudy (fionacndg):

OHHHh I get this now! thank you somuch! @IMStuck

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