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Mathematics 17 Online
OpenStudy (anonymous):

Can someone please explain to me? Trigonometry http://i59.tinypic.com/2v3oc42.jpg

OpenStudy (anonymous):

#11 or #14 please

OpenStudy (anonymous):

@ramit.dour @neoh147

OpenStudy (anonymous):

u want value of x ?

OpenStudy (anonymous):

The question is asking to proof that the left side is equal to the right side of the equation.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

Thank you @ramit.dour

OpenStudy (anonymous):

wait , doing it

OpenStudy (anonymous):

Ok! c:

OpenStudy (anonymous):

always use most complex side to prove...

OpenStudy (anonymous):

|dw:1406093548454:dw|

OpenStudy (anonymous):

as|dw:1406093613859:dw|

OpenStudy (anonymous):

(1+sec x)/(sin x+ tan x)=csc x LHS =(1+(1/cos x))/(sin x+sin x/cos x) =(1+(1/cos x))/sin x(1+1/cos x) =1/sin x = csc x =RHS Prove

OpenStudy (anonymous):

Thank you so much @neoh147

OpenStudy (anonymous):

welcome @study100

OpenStudy (anonymous):

tan x / (tan x + sin x) = (1- cosx) /sin^2 x LHS =tan x / (tan x + sin x) =tan x / (tan x + cos x tan x) sin x = cos x tan x =tan x / (tan x)(1+cos x) =1/ (1+cos x) times both numerator and denominator with conjugate of 1+ cos x = (1- cos x)/ 1- cos^2 x = (1- cos x)/ sin^2 x 1 = sin^2 x + cos^2 x

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