Can someone please explain to me? Trigonometry
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OpenStudy (anonymous):
#11 or #14 please
OpenStudy (anonymous):
@ramit.dour @neoh147
OpenStudy (anonymous):
u want value of x ?
OpenStudy (anonymous):
The question is asking to proof that the left side is equal to the right side of the equation.
OpenStudy (anonymous):
okay
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OpenStudy (anonymous):
Thank you @ramit.dour
OpenStudy (anonymous):
wait , doing it
OpenStudy (anonymous):
Ok! c:
OpenStudy (anonymous):
always use most complex side to prove...
OpenStudy (anonymous):
|dw:1406093548454:dw|
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OpenStudy (anonymous):
as|dw:1406093613859:dw|
OpenStudy (anonymous):
(1+sec x)/(sin x+ tan x)=csc x
LHS
=(1+(1/cos x))/(sin x+sin x/cos x)
=(1+(1/cos x))/sin x(1+1/cos x)
=1/sin x
= csc x
=RHS Prove
OpenStudy (anonymous):
Thank you so much @neoh147
OpenStudy (anonymous):
welcome @study100
OpenStudy (anonymous):
tan x / (tan x + sin x) = (1- cosx) /sin^2 x
LHS
=tan x / (tan x + sin x)
=tan x / (tan x + cos x tan x) sin x = cos x tan x
=tan x / (tan x)(1+cos x)
=1/ (1+cos x)
times both numerator and denominator with conjugate of 1+ cos x
= (1- cos x)/ 1- cos^2 x
= (1- cos x)/ sin^2 x 1 = sin^2 x + cos^2 x