Question

Need Help!

Answer 1

What is the maximum value of \(sin \ \theta\) ?

Answer 2

Not sure?

Answer 3

Value of \(sin \theta \) oscillates between -1 and 1. So maximum value of \(sin \theta\) can take is 1. Put this value and get the result.

Answer 4

@SolomonZelman

Answer 5

Maximum of value of \(sin\left(\frac{\pi}{12}(x-2)\right)\) is 1. Put it it in \(-2 + 5sin\left(\frac{\pi}{12}(x-2)\right)\)

Answer 6

kinda lost?

Answer 7

the value of \(-2+5sin \left(\frac{\pi}{12}(x-2)\right)\) is maximum if \(sin \left(\frac{\pi}{12}(x-2)\right)\) is maximum. \(sin \left(\frac{\pi}{12}(x-2)\right)\) has maximum value 1. You don't need to think about x.
So the maximum value is \[-2+5sin \left(\frac{\pi}{12}(x-2)\right)= -2 + 5 \times 1 = -2+5 = 3\]

Answer 8

So the max value would be 3?

Answer 9

Yes

Answer 10

Thank you!