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If tan x° = z/10 and cos x° = 10/y, what is the value of sin x°? a. sin x° = z/y b. sin x° = y/z c. sin x° = 10z d. sin x° = 10y
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\[\tan \theta=\frac{ \sin \theta }{ \cos \theta}\]just solve for sin
and then plug in what you have for cos and tan
Would it be x° = y/z?
\[\sin \theta = \tan \theta \cdot \cos \theta = \frac{ z }{10 }\cdot \frac{ 10 }{ y } = \frac{ z }{\cancel{10} }\cdot \frac{ \cancel{10} }{ y } =\frac{ z }{ y }\]
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Oh, right. I can be a real dunce when it comes to Geometry. Thanks pilot! :)
just remember the basic trig relationships... and don't sweat it, we ALL make mistakes! here's a quick trig cheat sheet for you...
That's a pretty cool sheet. Many thanks! :)
you're welcome!
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