Question

I have another one Please help
Complete the table
[H30+] [OH] pOH pH Acidic or Basic
1.0 X 10-8 1.0 X 10-6 6.00 8.00 basic
3.55
1.7 X 10-9
13.5
8.6 X 10-11

Answer 1

Here is a better chart

Answer 2

pH + pOH =14

Answer 3

pH = -log[H30+]

Answer 4

pOH = -log[OH-]

Answer 5

Can you find pOH for the second row?

Answer 6

@tntbice15?

Answer 7

sorry don't understand

Answer 8

Let's take it one step at a time. Can you use pH + pOH = 14 to solve for pOH in the second line?

Answer 9

This class has me completely lost....the text doesn't even explain how to do this.....do you use the mass of each?

Answer 10

No, not for pH and pOH.

Answer 11

If you plug in the pH into the formula:
3.55 + pOH = 14

Answer 12

Can you solve for pOH?

Answer 13

Here is some good info on the subject: http://www.chem.purdue.edu/gchelp/howtosolveit/Equilibrium/Calculating_pHandpOH.htm

Answer 14

10.45? I am really lost I don't know where the numbers have come from in the first place

Answer 15

I always hate when textbooks don't explain things well!

Answer 16

Right! :)

Answer 17

It doesn't help I never took chemistry in High school and high school was 25 years ago

Answer 18

Wow, yeah, it is tough to start back!

Answer 19

where did you get 14 from?

Answer 20

That's the formula.

Answer 21

ok

Answer 22

Here is some info on why. http://www.chem.purdue.edu/gchelp/howtosolveit/Equilibrium/Calculating_pHandpOH.htm

Answer 23

ok getting those numbers seems easy enough (at least when I have one of them) but how do I get the other parts of the graph

Answer 24

The way to relate pH and [H30+] is
pH=-log[H3O+]

Answer 25

Can you find [H3O+] for the second line?

Answer 26

Do you remember how to work with logs?

Answer 27

not a clue

Answer 28

Let me rearrange it for you to solve for [H3O+}.