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Mathematics 7 Online
OpenStudy (anonymous):

HELP!!!!!! Will fan and medal

OpenStudy (anonymous):

OpenStudy (anonymous):

Hint: The triangle is a isosceles right angle triangle.

OpenStudy (anonymous):

Oh, So it's the 45,45,90

OpenStudy (anonymous):

Right!

OpenStudy (anonymous):

I have another question

OpenStudy (anonymous):

A square television screen has a side length of 10 inches. What is the approximate length of the diagonal of the television screen? A. 10 inches B. 14 inches C. 20 inches D. 100 inches

OpenStudy (anonymous):

Post it and tag me

OpenStudy (anonymous):

@ShailKumar

OpenStudy (anonymous):

Can you calculate it ?

OpenStudy (anonymous):

I thought it was 10+10+10+10 Because it is a square T.V. screen

OpenStudy (anonymous):

|dw:1406148112449:dw| You need to calculate AC..

OpenStudy (anonymous):

AC (or BD) is the diagonal of the screen. Do you know Pythagoras theorem ?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Apply Pythagoras theorem and calculate AC.

OpenStudy (anonymous):

pythagorean theorem

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

1 min still calculating

OpenStudy (anonymous):

I got 60

OpenStudy (anonymous):

That is wrong !

OpenStudy (anonymous):

I know that But I did a^2 x c^2

OpenStudy (anonymous):

Show me your steps

OpenStudy (anonymous):

I messed up it was 40!

OpenStudy (anonymous):

Actually, it is \(AC^2 = AB^2 + BC^2\) Can you calculate now ?

OpenStudy (anonymous):

It's not 40?

OpenStudy (anonymous):

Yes, it's not 40.

OpenStudy (anonymous):

20!!!

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

Can you calculate or not ?

OpenStudy (anonymous):

I guess not . _.

OpenStudy (anonymous):

OK

OpenStudy (anonymous):

AB = 10 inches and BC = 10 inches. RIGHT?

OpenStudy (anonymous):

Right

OpenStudy (anonymous):

So, \(AC^2 = AB^2 + BC^2 = 10^2 + 10^2 = 100+100 = 200\) i.e \(AC = \sqrt{200} \) Can you calculate \(\sqrt{200}\) ?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

What is it ?

OpenStudy (anonymous):

14.1421356237

OpenStudy (anonymous):

Correct!

OpenStudy (anonymous):

So, wait that was the answer the whole time O_O

OpenStudy (anonymous):

@ShailKumar I have one more A banner is in the shape of a 30°–60°–90° triangle. The shorter leg has a length of 30 inches. What is the approximate length of the longer leg? A. 15 inches B. 42 inches C. 52 inches D. 60 inches

OpenStudy (anonymous):

I believe it's 60 but I'm not sure

OpenStudy (anonymous):

Do you know about trigonometry ?

OpenStudy (anonymous):

Not really

OpenStudy (anonymous):

I know some Trigonometry

OpenStudy (anonymous):

@ShailKumar you still there?

OpenStudy (anonymous):

OK. |dw:1406151324534:dw|

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