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OpenStudy (anonymous):
OpenStudy (anonymous):
Hint: The triangle is a isosceles right angle triangle.
OpenStudy (anonymous):
Oh, So it's the 45,45,90
OpenStudy (anonymous):
Right!
OpenStudy (anonymous):
I have another question
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OpenStudy (anonymous):
A square television screen has a side length of 10 inches. What is the approximate length of the diagonal of the television screen?
A.
10 inches
B.
14 inches
C.
20 inches
D.
100 inches
OpenStudy (anonymous):
Post it and tag me
OpenStudy (anonymous):
@ShailKumar
OpenStudy (anonymous):
Can you calculate it ?
OpenStudy (anonymous):
I thought it was 10+10+10+10 Because it is a square T.V. screen
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OpenStudy (anonymous):
|dw:1406148112449:dw|
You need to calculate AC..
OpenStudy (anonymous):
AC (or BD) is the diagonal of the screen. Do you know Pythagoras theorem ?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Apply Pythagoras theorem and calculate AC.
OpenStudy (anonymous):
pythagorean theorem
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OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
1 min still calculating
OpenStudy (anonymous):
I got 60
OpenStudy (anonymous):
That is wrong !
OpenStudy (anonymous):
I know that But I did a^2 x c^2
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OpenStudy (anonymous):
Show me your steps
OpenStudy (anonymous):
I messed up it was 40!
OpenStudy (anonymous):
Actually, it is \(AC^2 = AB^2 + BC^2\)
Can you calculate now ?
OpenStudy (anonymous):
It's not 40?
OpenStudy (anonymous):
Yes, it's not 40.
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OpenStudy (anonymous):
20!!!
OpenStudy (anonymous):
Nope
OpenStudy (anonymous):
Can you calculate or not ?
OpenStudy (anonymous):
I guess not . _.
OpenStudy (anonymous):
OK
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OpenStudy (anonymous):
AB = 10 inches and BC = 10 inches. RIGHT?
OpenStudy (anonymous):
Right
OpenStudy (anonymous):
So, \(AC^2 = AB^2 + BC^2 = 10^2 + 10^2 = 100+100 = 200\)
i.e \(AC = \sqrt{200} \)
Can you calculate \(\sqrt{200}\) ?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
What is it ?
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OpenStudy (anonymous):
14.1421356237
OpenStudy (anonymous):
Correct!
OpenStudy (anonymous):
So, wait that was the answer the whole time O_O
OpenStudy (anonymous):
@ShailKumar I have one more
A banner is in the shape of a 30°–60°–90° triangle. The shorter leg has a length of 30 inches.
What is the approximate length of the longer leg?
A.
15 inches
B.
42 inches
C.
52 inches
D.
60 inches
OpenStudy (anonymous):
I believe it's 60 but I'm not sure
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