In how many ways can a teacher arrange five students in the front row of a classroom with a total of 23 students?

4,037,880

3,037,880

2,037,880

1,037,880

Question

In how many ways can a teacher arrange five students in the front row of a classroom with a total of 23 students?
		
4,037,880
		
3,037,880
		
 2,037,880
		
1,037,880

anonymous · Answer

$$\large{}_{23}P_{5}=\frac{23!}{(23-5)!}$$
assuming order matters. It looks to be the case because, presumable, every student is different from each other.

solomonzelman · Answer

Yes, SithAndGiggles is right, and the order does matter (from the wording of the problem). This is a calculator to avoid problems with calculations. http://www.calculatorsoup.com/calculators/discretemathematics/permutations.php

anonymous · Answer

thnx

anonymous · Answer

You can also arrive at this conclusion by seeing that $\dbinom{23}5$ isn't an option :P

anonymous · Answer

nah mine is words

anonymous · Answer

its so hard they dont give you any equations or formula its theyre just words

anonymous · Answer

for example like this

anonymous · Answer

Find the number of ways to listen to four CDs from a selection of eight CDs.

anonymous · Answer

Hmm yeah that wording is pretty vague. If you're not selective about the playlist, you'd you ${}_{8}C_{4}$, but there's no way to know for sure...