What is the equation of the line that passes through (12, 4) and is perpendicular to the graph of y = -3 over 4x - 2? y = 4 over 3x - 12 y = 3 over 4x - 5 y = -4 over 3x + 20 y = -3 over 4x + 13
first take out the slope of from the given equation y=mx+b always constant term in this type of equation is yur slope so here what will be the slope it is yur job to find the slope here
-3/4
and reverse it because x is in the denominator so it will become m=-4/3
so its C
our work is not done still ... @kellyconnelly
y = -4/3x + 20
here the line is perpendicular so use this condition of slope here m1m2=-1 and m1=-4/3 (-4/3)m2=-1 m2 = 3/4
now u can answer the question logically that which one is correct
B is the correct answer
now use here the point slope form and get the answer which is B
k @kellyconnelly is it \[y = \frac{ -3 }{ 4x-2 } ......... or............ y = \frac{ -3 }{ 4x } -2....? \]
omg......... which one...... the first one or the second one??
if it is second one then A is the correct answer
@kellyconnelly tell me how the equation is written in yur book
its neither
its 3/4 and then an x
\[\frac{ 3 }{ 4 }x\] but negative
@Haseeb96 @driftracer305
so A is the correct answer
@kellyconnelly just revise the method again because in the previous i thought that it is -3/4x and x is the denomenator but i was wrong it is in the numenator
so here we have no need to reverse it just put the slope into the perpendicular condition and get the answer
\[y = -\frac{ 3 }{ 4 }x - 2\]
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