Which point is a solution for this system of inequalities? y < 2x + 1 y > -x - 1 (1, 10) (-5, 1) (-12, 12) (0, 0)
Using trial and error I tried (0,0) first and I got: 0 < 2(0) + 1 0 > -0-1 which gives 0 < 1 and 0 > -1.
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You want to know which point is a solution for the inequalities. The easiest way would be to just substitute the options given into your inequalities. The easiest one to try is (0,0), i.e. x = 0 and y = 0. Substituting into y < 2x + 1 will give you: 0 < 2(0) + 1 Simplify that to get: 0 < 1 which is TRUE. Now substitute into: y > -x - 1 which gives: 0 > -0 -1, i.e. 0 > -1 which is also TRUE. Therefore (0,0) is one solution for your inequalities. As they only need one solution your work is done.
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