cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5
Help Please!
@Haseeb96
@ilikemath50
Did not learn cube roots yet, Can't help you there, sorry
Dang
do you know anyone
I'll try to send someone else in, @precal @thomaster @iambatman
Thank you!
No problem! :)
Im new to this like I just started
@superhelp101
Yeah, when I just started all I did was ask questions, but im pretty good at math so I was like hey! why not help people with their questions? I have gotten quite a few medals and fans now.. I could do better though, lol
give me a moment to try to post the equation
Ok thanks :)
\[\frac{ \sqrt[3]{5}\sqrt{5} }{ \sqrt[3]{5^5} }\] is this your problem?
Yes
ok lets rewrite it using fractions
Ok
here are my answer choices
\[\frac{ 5^{1/3}5^{1/2} }{ 5^{5/3} }\]
don't need your choices
ok
ok what is x times x?
1
no x times x is x^2 (x to the second power)
Ohh
I understand that
why is this true? because we added the powers so \[x^1(x^2)=x^3\]
ok we do need the same base for this to be true, btw this is one of your laws of exponents
so do the top of the fraction for me
ok you have to add the exponents
5 5/6
because i did 1/3 = 2/6 then 1/2 =3/6 right? @precal
yes it is 5 and 5/6
Yay ok now the next part
now this leads us to another law of exponent \[\frac{ x^3 }{ x }\] is what?
\[\frac{ x^3 }{ x }=\frac{ xxx }{ x }=xx=x^2\]
do you see the pattern for this law of exponent?
ya
I see
so its 5 5/6 over 5 5/3
\[\frac{ a^b }{ a^c }=a ^{b-c}\]
Hold on i gtg fix my blinds be back
ok
let me know when to continue
k im back @precal I had new windows put in and They took my blinds down
no problem, I fixed mine the other days.....I would rather solve math problems than real world house problems.....
ok so the bases are the same and we are going to subtract the exponents. Always do top exponent minus bottom exponent
Ok
so its 5 5/6 minus 5 5/3
\[\frac{ 5^{5/6} }{ 5^{5/3} }\]
would I make it 10/6
\[5^{\frac{ 5 }{ 6}-\frac{ 5 }{ 3 }}\]
should be -5/6
THANK YOU
\[5^{-5/6}\]
How can I like favorite you
Im new
well we are not done, leads us to another law of exponent,
O ok
mark response look for the blue rectangle that states "best response" this gives us medals and you can "fan me" if you want, I think you have to pick something on my name.....
last step
\[x ^{-2}=\frac{ 1 }{ x^2 }\]
so we have 5 -5/6
negative powers move things from numerator to denominator so x^-2 is a numerator and to get rid of the negative sign, we make it a denominator
\[\frac{ x^3y ^{-2} }{ z ^{-4} }\]
were did you get that?
ok see how y has a negative power and z has a negative power I am making up an example to help you understand the last step
Yes o ok
\[\frac{ x^3y ^{-2} }{ z ^{-4} }=\frac{ x^3z^4 }{ y^2 }\]
see how y went to the bottom and z went to the top
ok yes
computer is acting weird, I need to get a new mouse
Ok lol
So is 5 -5/6 the answer?
Or is there another part
sorry, my computer is acting weird. I had to switch out three mouses
\[\frac{ 1 }{ 5^{5/6} }\]
this is your final answer
Its doesnt show
sometimes the system gets rid when there are a lot of people on the site
get weird I meant
can you see it now
O wait I just rembered that the properties of exponents shows that if you have a 1 over the answer that it can be made into a negative answer!!!! so 5 -5/6 is right!!
\(\Large \bf { a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad \sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}} \\\quad \\ a^{-\frac{{\color{blue} n}}{{\color{red} m}}} = \cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}} \implies \cfrac{1}{\sqrt[{\color{red} m}]{a^{\color{blue} n}}} \\ \quad \\ \quad \\ \frac{ \sqrt[3]{5}\sqrt[2]{5} }{ \sqrt[3]{5^5} }\implies \cfrac{5^{\frac{1}{3}}\cdot 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}\implies \cfrac{5^{\frac{1}{3}}\cdot 5^{\frac{1}{2}}}{1}\cdot \cfrac{1}{5^{\frac{5}{3}}} \\ \quad \\ 5^{\frac{1}{3}}\cdot 5^{\frac{1}{2}}\cdot 5^{-\frac{5}{3}}\implies 5^{\frac{1}{3}+\frac{1}{2}-\frac{5}{3}=\frac{4+6-20}{12}=\frac{-\cancel{ 10 }}{\cancel{ 12 }}=\frac{-5}{6}} \\ \quad \\ 5^{\frac{-5}{6}}\implies \cfrac{1}{5^{\frac{5}{6}}}\implies \cfrac{1}{\sqrt[6]{5^5}} }\)
THANK YOU GUYS SO MUCH ILL TELL YOU IF I GET IT RIGHT!!!
yes but it is best to get rid of negative exponents
anytime
I actually have a couple more ill post them
sure, close this problem out and open a new thread please
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