Question

A solution is made by dissolving 1.00 moles of sodium chloride (NaCl) in 155 grams of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem.

Answer 1

@Abmon98

Answer 2

@thomaster @paki

Answer 3

ΔT = Kb*m

Answer 4

Can you find the molality of the solution?

Answer 5

molality = 1.00 mol/ 0.155 Kg = 6.45
delta T = m x kb x i
i = Vant'Hoff factor for NaCl = 2

delta T = 6.45 x 0.51 x 2 = 6.6
boiling point = 100 + 6.1 = 106.1 °C
this is what i did is it right?

Answer 6

Yes, I get the delta T to be 6.6. 100+6.6 is what?

Answer 7

106.6?

Answer 8

:)

Answer 9

oh so is the boiling point is is 106.6?

Answer 10

That's what I get.

Answer 11

thank you!!

Answer 12

No worries. :)