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Simplify. square root of 5 over cube root of 5
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@precal @jdoe0001
\(\Large\color{blue}{ \frac{ \sqrt{5} } {\sqrt[3]{5}}= \frac{ \sqrt[2]{5} } {\sqrt[3]{5}}=\frac{5^{1/2}}{5^{1/3}} =5^{1/2-1/3} =5^{3/6-2/6} =5^{1/6} }\)
You can re-write this as \(\huge\color{black}{ \bf \sqrt[6]{5} }\)
Thanks! @SolomonZelman that makes so much sense!
Anytime:) Good luck on your homework !
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Yea :)
remember use your laws of exponents, this problem is just like the first one I helped you with
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