Kelly tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," Kelly explains. Using complete sentences, demonstrate to Kelly how the equation is still solvable.

Question

anonymous · Answer

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anonymous · Answer

@bakonloverk  @berrypicking  @beccamarx19

anonymous · Answer

@Brialynn96  @brittany210

anonymous · Answer

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anonymous · Answer

@Destinymasha @driftracer305 @D3xt3R @dhirensharma @dijahx3

anonymous · Answer

@esshotwired  @Elsa213  @eric_d

driftracer305 · Answer

well i guess it can be anything from 1/0 to..... 99/0 or whatever....... so since it will be in denominator  the variable will be like so.... say for example:-

$$\frac{ 5 }{ x } ........... x = 4/0......... \frac{ 5 }{ 4/0 }......... \frac{ 5*0 }{ 4 }.......\frac{ 0 }{ 4 }... = 0$$
................................

anonymous · Answer

But do i knwo that it can be solvable, how do i put that into words

driftracer305 · Answer

say that u can take the denominator as a fraction as well........ so like i did  5 over (4 over zero)...........so zero goes up with 5 and 4 stays down.......that way u have 0 over 4  which is still solvable.............

driftracer305 · Answer

@keishathelove101 ......... all good?

anonymous · Answer

yes