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I need serious help on this! What is the inverse of the given function? y = 7x^2 - 3.
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isnt inverse when you switch the x and y
To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
x = 7y^2 - 3
\[7y^2 = x + 3 \] \[y^2 = \frac{x+3}{7} => \]
\[\sqrt{(1/7)y+(3/7)},-\sqrt{(1/7)y+(3/7)}\]
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I was thinking like wouldn't it be: \[x=\pm \sqrt{\frac{ x+3 }{ 7 }}\]
bingo! but should be y =....
So i'm correct. Right?
ya
Thanx guys!!:D I appreciate your help:D I hate doing these. They seriously give me a hard time.
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