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How many liters of 15.0 molar NaOH stock solution will be needed to make 20.0 liters of a 1.2 molar NaOH solution? Show the work used to solve this problem.
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Hello @chariety101 ! Use \(\large \sf M_1V_1=M_2V_2\). Where \(\sf M_1,~V_1\) is the molarity and volume of stock solution and \(\sf M_2,~V_2\) is the molarity and volume of required solution.
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