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Use basic identities to simplify the expression tan theta/sec theta
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@jdoe0001
\(\bf tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\qquad sec(\theta)=\cfrac{1}{cos(\theta)}\quad thus\quad \\ \quad \\ \cfrac{tan(\theta)}{sec(\theta)}\implies \cfrac{\frac{sin(\theta)}{cos(\theta)}}{\frac{1}{cos(\theta)}}\) so.. what would that give you?
sin theta?
@jdoe0001
yeap \(\bf \cfrac{tan(\theta)}{sec(\theta)}\implies \cfrac{\frac{sin(\theta)}{cos(\theta)}}{\frac{1}{cos(\theta)}}\implies \cfrac{sin(\theta)}{\cancel{ cos(\theta) }}\cdot \cfrac{\cancel{ cos(\theta) }}{1}\)
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