Question

find the general solution:

(2x-3y)dx + (2y-3x)dy = 0


I got y^2 = c[(x/y)^2 - 3(x/y) +1 ]

but the books says the answer is:
x^2 + y^2 =3xy + c

is my answer still correct?

Answer 1

I got it now.
I made a mistake with ln.
:)

Answer 2

it should be:
y^2[(x/y)^2 - 3(x/y) +1 ] = c
then simplify :)

Answer 3

Looks good to me haha.