Question

What is the center of the circle that has a diameter whose endpoints are (2, 7) and (-6, -1)?



(4, 3)

(-2, 4)

(-2, 3)

Answer 1

you need to find the midpoint between them.

Answer 2

do you know the midpoint formula?

Answer 3

No i don't.

Answer 4

ok. the formula is ( give me a moment to type...)

Answer 5

\[(x _{1}+x _{2})\div2,(y _{1}+y _{2})\div2\]

Answer 6

\(\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 2}}\quad ,&{\color{blue}{ 7}})\quad &({\color{red}{ -6}}\quad ,&{\color{blue}{ -1}})
\end{array}\qquad
\left(\cfrac{{\color{red}{ x_2}} + {\color{red}{ x_1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ y_2}} + {\color{blue}{ y_1}}}{2} \right)\)

Answer 7

yes. thank you

Answer 8

ok so it would be (2+[-6])/2 (7+[-1])/2 so (-4,6)?

Answer 9

you forgot to devide by two i think

Answer 10

wait no it would be -2,3

Answer 11

yeah divide both the x and the y by 2

Answer 12

wait no it would be -2,3 \(\checkmark\)

Answer 13

good job

Answer 14

Thank you for your help :)

Answer 15

yw

Answer 16

your welcome. it was mostly jd thouh.. haha

Answer 17

haha, you started it out

Answer 18

:)