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Simplify. cuberoot(125n^12)
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\[\sqrt[3]{125n^{12}}\]
the a should be a 3
What's another way you could write this using a fractional exponent?
i have no clue.
How about this:\[(125n^{12})^\frac{1}{3} \]
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Now using rules of exponents, what should you get for n^12 raised to the 1/3?
And for 125, actually.
The rule for exponents is that you multiply, so now you have \[125^\frac{1}{3}*(n^{12})^\frac{1}{3}\]
Oh ok, so then i would have 5n^4?
Bingo! :)
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Awesome, thanks!
Happy to help.
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