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Mathematics 9 Online
OpenStudy (anonymous):

Factor

OpenStudy (anonymous):

\[-18x ^{4}+18x ^{3}+12x-12\]

OpenStudy (campbell_st):

well start by grouping in pairs (-18x^4 + 18x^3) + (12x - 12) remove common factors from each pair... what do you get

OpenStudy (anonymous):

\[\frac{ -18x ^{4} }{ -18x ^{3} } \]

OpenStudy (anonymous):

\[\frac{ +18x ^{3} }{ -18x ^{3} }\]

OpenStudy (anonymous):

(x+1) ?

OpenStudy (campbell_st):

well not quite -18x^3 is a common factor and in the other pair you get 12 so its -18x^3(x - 1)+ 12(x -1) which gives (-18x^3 + 12)(x - 1) so take out -6 and you get -6(3x^3 + 2)(x - 1) and I'd say that's the answer

OpenStudy (anonymous):

Oh, thank you :)

OpenStudy (campbell_st):

oops the final answer should be -6(3x^3 - 2)(x -1)

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