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What is the vertex of the parabola given by y = -(x − 2)2 − 1? (2, 1) (2, -1) (-2, 1) (-1, 2)
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\[y = ax ^{2} + bx + c.\] thats how you find the vertex now make your equation into a proper equation.
is it meant to be \[-(x-2)^{2}\]
whats the answer?
you need to answer my question first so i can figure it out
yes
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\[(x-2)(x-2)=x ^{2}-4x+4\] \[-(x ^{2}-4x+4)2-1\] \[-x ^{2}+4x-2\] go from there and do the rest of the equation when you have a full equation the first spot is a second is b and third is c plug it in to the first equation i gave you and you'll have your answer
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