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Mathematics 10 Online
OpenStudy (anonymous):

What is the center of the circle given by the equation (x - 3)2 + (y - 9)2 = 16? A. (3, 9) B. (-9, -3) C. (9, 3) D. (-3, -9)

OpenStudy (anonymous):

A

OpenStudy (anonymous):

ah no sorry

OpenStudy (anonymous):

plug in the x and y values and see which ones give you 16

OpenStudy (mrnood):

the general equation of a circle is \[(x-a)^{2}+(y-b)^{2}= r ^{2}\] where (a,b) is the centre of the circle and r is the radius

OpenStudy (mrnood):

compare that to YOUR equation and hence derive (a,b)

OpenStudy (anonymous):

MrNood, can you help me with my question? and the answer is A

OpenStudy (anonymous):

since the radius is 4

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