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Mathematics 17 Online
OpenStudy (superhelp101):

Write the general form of the equation which matches the graph below. In complete sentences, explain the process taken to find this equation.

OpenStudy (superhelp101):

OpenStudy (superhelp101):

@amistre64 can you help me? :) plz

OpenStudy (amistre64):

found it

OpenStudy (superhelp101):

yay :)

OpenStudy (amistre64):

so you need to explain how to find a parabola equation from this

OpenStudy (superhelp101):

yes

OpenStudy (xapproachesinfinity):

looks like y=4 is a directrex and A is the focus, no?

OpenStudy (amistre64):

since a method is involved, and most likely the geometric definition is involved ... my idea wont have much merit

OpenStudy (amistre64):

i would use the vertex form: y = a(x-h)^2 + k input the vertex values for (h,k) and find a by using a latus rectus point ... thats a point on the parabola that is in line with the focus.

OpenStudy (superhelp101):

so I need to use the vertex form to make the equation?

OpenStudy (amistre64):

you need to use what your material wants you to use. i have no material, just a way that a solution can be found.

OpenStudy (superhelp101):

oh okay, I don't think it shows any specific way I need to use, is that what you would do?

OpenStudy (amistre64):

i would use the vertex form, and deduce from the focus (a,b) that a point in the parabola is some (a+c, b) where c is the distance from the vertex to the focus

OpenStudy (superhelp101):

okay, can you help me do that? ;)

OpenStudy (amistre64):

i spose ... we know the form will take on: y = -a(x-h)^2 + k right? can you tell me the values of h and k?

OpenStudy (superhelp101):

is h is 3 and k 0

OpenStudy (amistre64):

good, y = -a(x-3)^2 all we need is a point on the parabola to define the missing variable. by properties of a parabola, all points are the same distance from the focus as they are from the directrix right? so we can use a latus rectus point, fancy name for the point that is beside the focus |dw:1406572694312:dw|

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