Question

Adult tickets to the fall play cost $8 and student tickets cost $4. The drama class sold 30 more adult tickets than student tickets to the fall play. If the class collected $840 from ticket sales, how many adult tickets were sold?

The drama class sold _____ adult tickets.

Answer 1

@olipop2002

Answer 2

@mathmale

Answer 3

Adult tickets =x
student ticket = y

so dollars *tickets = total sales

first equation
8x+4y = 840

what else do we know?
we know that 30 more adult tickets were sold
adult tickets=student tickets + 30

or equation 2
x=y+30 or putting the variables on one side
x-y=30

do you still need help?? can u get it from here?

Answer 4

hello??

Answer 5

yes

Answer 6

can u get it from here?

yes

ok

Answer 7

so?

Answer 8

can u solve it now???

Answer 9

i dont know

Answer 10

i feel stupid

Answer 11

no do not feel stupid just something you have not learned yet

Answer 12

it's like i have learned it, but over the break i forgot how to solve it.

Answer 13

lets pick up where we left off

we need to find one of the variables (x or y) and then we can get the other

lets add the 2 equations together to eliminate a variable:

8x+4y = 840
x- y= 30

to eliminate a variable, lets multiply the 2nd eqaution by 4, you will see why.

8x+4y = 840
4x - 4y=120 now add and we remove y
________________
12x + 0 = 960 getting x by itself we divide both sides by 12

12x/12 = 960/12

x=???

Answer 14

80?

Answer 15

correct --so we sold 80 adult tickets

now we find y or student tickets by plugging x in the 2nd equation.

80 - y =30 add y both sides and also subtract 30

80 - 30 + y-y = 30 - 30 + y we get
50 = y

50 student tickets are we done

no!!


lets do a check by putting in our found values.

8(80) + 4(50) = 840 it checks


go over the steps again and remember that you have 2 unknowns adult tickets and student tickets


2 unknowns 2 equations and so on.