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3x^2+4x-2=0
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quadratic formula?
x=-2/3 x=1
yes, and i need to show my work.
I don't think it's x= -2/3, you need to use the quadratic formula.
x^2-4x+6 = 0 (x+2/3) (x-3/3) (3x+2)(x-1)
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but (3x+2)(x-1) = 3x^2 -3x +2x -2 = 3x^2 -x -2 incorrect D:
again, quadratic formula just use it.
im not sure how to do that.
\[\frac{ -b \pm \sqrt{b^{2} + 4ac} }{ 2a}\] and we also have \[ax^{2} + bx +c\] in this case a= 3 b= 4 c= -2 All you need to do is plug a, b , and c in the equation then simplify
plug it in the first equation
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Alright, thank you
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