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Mathematics 15 Online
OpenStudy (anonymous):

3x^2+4x-2=0

OpenStudy (anonymous):

quadratic formula?

OpenStudy (anonymous):

x=-2/3 x=1

OpenStudy (anonymous):

yes, and i need to show my work.

OpenStudy (anonymous):

I don't think it's x= -2/3, you need to use the quadratic formula.

OpenStudy (anonymous):

x^2-4x+6 = 0 (x+2/3) (x-3/3) (3x+2)(x-1)

OpenStudy (anonymous):

but (3x+2)(x-1) = 3x^2 -3x +2x -2 = 3x^2 -x -2 incorrect D:

OpenStudy (anonymous):

again, quadratic formula just use it.

OpenStudy (anonymous):

im not sure how to do that.

OpenStudy (anonymous):

\[\frac{ -b \pm \sqrt{b^{2} + 4ac} }{ 2a}\] and we also have \[ax^{2} + bx +c\] in this case a= 3 b= 4 c= -2 All you need to do is plug a, b , and c in the equation then simplify

OpenStudy (anonymous):

plug it in the first equation

OpenStudy (anonymous):

Alright, thank you

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