Question

8x^2+7x-3=0 and 7c^2-2c=1.

Answer 1

use quadratic formula for solving
ax^2 +bx+c = 0

\[x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\]

Answer 2

thank you!

Answer 3

yw :)

Answer 4

i dont think im doing this right can you help me?

Answer 5

@dumbcow

Answer 6

ok for #1

a = 8
b=7
c =-3

\[x = \frac{-7 \pm \sqrt{7^2 - 4(8)(-3)}}{2(8)}\]

Answer 7

i got that part, but im getting weird numbers when i try and solve it

Answer 8

\[\frac{-7 \pm \sqrt{145}}{16}\]
those weird numbers ?
those are correct

Answer 9

no i must have been doing it wrong. is that the answer?

Answer 10

yeah

Answer 11

alright thanks so much

Answer 12

7^2 = 49

4*8*3 = 96

96+49 = 145

Answer 13

can i ask you one more question?

Answer 14

sure

Answer 15

nevermind i figured it out thanks

Answer 16

ok